2x^2+8x+20=4

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Solution for 2x^2+8x+20=4 equation: 



2x^2+8x+20=4

We move all terms to the left:

2x^2+8x+20-(4)=0

We add all the numbers together, and all the variables

2x^2+8x+16=0

a = 2; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·2·16
Δ = -64
Delta is less than zero, so there is no solution for the equation

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